(2/3)x-1/3 + (2/3)y-1/3 y' = 0, so that (Now solve for y'.) (2/3)y-1/3 y' = - (2/3)x-1/3, and, Since lines tangent to the graph will have slope $ -1 $, set y' = -1, getting, - y 1/3 = -x 1/3, y 1/3 = x 1/3, ( y 1/3) 3 = ( x 1/3) 3, or y = x. Substitue this into the ORIGINAL equation x 2/3 + y 2/3 = 8, getting x 2/3 + (x) 2/3 = 8, 2 x. B-c = (1–2+3–4+5–6⋯)-(1+2+3+4+5+6⋯) Because math is still awesome, we are going to rearrange the order of some of the numbers in here so we get something that looks familiar, but.
![2/3 2/3](https://d3i71xaburhd42.cloudfront.net/3bd989cab6fc4b45fee6decb4530ff2dff4bc485/6-Figure2-1.png)
Readkit 2 6 3 Equals 2/3
![Readkit 2 6 3 equals many Readkit 2 6 3 equals many](https://ars.els-cdn.com/content/image/1-s2.0-S0743731517301314-fx2.jpg)
Readkit 2 6 3 Equals Inches
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Readkit 2 6 3 Equals 1/3
In each of these puzzles, you are given a number that you must construct out of several other numbers. You do this by taking the numbers and performing addition, subtraction, multiplication, and/or division operations on them. Each number must be used in the calculations exactly once, and only these four operations listed may be used. You may parenthesize your expression however you wish. For example, 5 may be obtained from 1, 2, and 3, with the expression (3 + 2) × 1. In many if not most cases, multiple solutions are possible, but usually only one is given on the solution page.
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